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August 29, 2014

August 29, 2014

Posted by **kkjhjkh** on Tuesday, April 14, 2009 at 12:36am.

F(x) = 0, X<0

X^3, 0<X<1;

1, 1<X

Then the mean for this random variable is:

I don't understand how to do CDF (cumulitive distribution function) or how to get the mean of it. Thank You!

- Calculus -
**drwls**, Tuesday, April 14, 2009 at 5:34amThe average or mean of a distribution F(x) is the integral of F(x)dx

(which in this case = 1/4 when the limits are 0 and 1) divided by the width of the interval (which in this case = 1). So the answer is 1/4.

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