Sunday

April 20, 2014

April 20, 2014

Posted by **Michael** on Sunday, April 12, 2009 at 11:36pm.

what is the magnitude of the time average force?

>>First I found the impulse delivered by the wall which is Px'-Px (momentum) = .096 N/s. Then I tried to find the change in time by taking (.5*2*(1/1000))/12. For this change in time i got 8.33E-4. However, the answer .096/8.33E-4 was incorrect. Help!

- Physics -
**drwls**, Sunday, April 12, 2009 at 11:55pmThe average velocity from first impact to turnaround (maximum compression) is 6 m/s. The time required to reach maximum compression (at constant acceleration) is T = 0.5 cm/(600 cm/s)= 8.3*10^-4 s. Acceleration is

a = (delta V)/T

a = (12 m/s)/(8.3*10^-4s) = 14,400 m/s^2

M = m a = (0.004 kg)(14,400 m/s^2) = 57.6 N

I understand how you got the impulse. The units of momentum are not N/s. The time agrees with mine, but mine is half the total interval of contact, and yours is the total time of contact. Something is wrong there

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