Posted by some kid on .
The position of a particle moving on the xaxis at time t>0 seconds is: x(t)= e^t  t^1/2.
a) Find the average velocity of the particel over the interval [1,3].
b) In what direction and how fast is the particle moving at t= 1 seconds?
c) For what values of t is the particle moving to the right?
d) Find the postition of the particle when its velocity is 0.

AP Calculus 
drwls,
a) Calculate the change in x from t=1 to t=3 and divide by 2 s for athe anverage velcoity
b) Calculate dx/dt at t=1
velocity = dx/dt = e^t  (1/2)/t^1/2
c) Find out when dx/dt > 0 . That will be the answer. You may need to graph dx/dt
d) Solve for t when dx/dt = 0
Use that t in the x(t) equation.
These are exercises you should be able to do yourself. Someone will gladly critique your work.