Posted by some kid on Sunday, April 12, 2009 at 7:40pm.
a) For the first quadrant region, x>0 to x = k, and the enclosed area is
Integral y dx =
Integral 2e^-x dx
x = 0 to k
= -2 e^-k + 2 e^0
= 2(1 - e^-k)
b) Make the integrand pi*y^2 dx and perform the resulting integration from 0 to k
c) This should be obvious after doing (b)
Related Questions
calculus - Which has more area, the region in the first quadrant enclosed by the...
calculus - Find the area of the region in the first quadrant enclosed by the ...
calculus - Let R be the region in the first quadrant that is enclosed by the ...
Calculus 1 - Let f be the function given by f(x)=3sqrt(x-2). A) On the axes ...
Calculus - Let f be the function given by f(x)=(x^3)/4 - (x^2)/3 - x/2 + 3cosx. ...
calculus - 1. Let R be the region in the first quadrant enclosed by the graphs ...
Calculus - Let R be the region in the first quadrant under the graph of y=1/sqrt...
calculus - Sketch the region in the first quadrant enclosed by the given curves...
Calc AB - What is the area of the region in the first quadrant enclosed by the ...
Calculus - I am doing the AP calculus review, these are the questions I have no ...
For Further Reading