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math sos.

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dURING THE FIRST PART OF A TRIP, A CONOEIST TRAVELS53 MILES AT A CERTAIN SPEED . The canoeist travels 9 miles on the second part of the tripat a speed 5 mph lower.The total time for the trip is 5 hrs, what was the speed on each part of the trip. The first part of the trip was ..... mph. (simplify your answer.type an integar or decimal.round to nearest hundreth).

  • math sos. - ,

    Speed (S) = Distance (D)/Time (T)

    Therefore T = D/S

    5 = 53/S + 9/(S-5)

    Solve for S.

    I hope this helps. Thanks for asking.

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