math sos.
posted by tera .
dURING THE FIRST PART OF A TRIP, A CONOEIST TRAVELS53 MILES AT A CERTAIN SPEED . The canoeist travels 9 miles on the second part of the tripat a speed 5 mph lower.The total time for the trip is 5 hrs, what was the speed on each part of the trip. The first part of the trip was ..... mph. (simplify your answer.type an integar or decimal.round to nearest hundreth).

Speed (S) = Distance (D)/Time (T)
Therefore T = D/S
5 = 53/S + 9/(S5)
Solve for S.
I hope this helps. Thanks for asking.