Tuesday

July 29, 2014

July 29, 2014

Posted by **Lauren** on Sunday, April 12, 2009 at 4:16pm.

So far this is what I have:

0=x^3 + 3/(x^2) +2

-2= (1/x^2)(x^5 + 3)

-2x^2= x^5 +3

But now I'm stuck. I also am not sure if this is how I'm supposed to be solving the problem. We had been learning Rolle's Theorem and the Mean Value Theorem, but none of those seem applicable here because they require that all points on the interval be differentiable, and if the function has a zero on the interval then it is not differentiable at that point. Am I going about this the right way? And how would I solve it from here?

**Related Questions**

unique solution - How do I show that the equation x^4 + 3x + 1 = 0, -2 <= x &...

math (calculus) PLZZZ help! - Consider the function below. (Round the answers to...

Algebra - What is the answer? I came up with C. is this correct? Thanks for the ...

calculus - interval of convergence - infinity of the summation n=0: ((n+2)/(10^n...

Taylor seires - f(x) =ln (1-x) a) Compute f'(x), f''(x), f'''(x). Spot the ...

calculus - interval of convergence - infinity of the summation n=0: ((n+2)/(10^...

calculus - For what value of the constant c is the function f continuous on the ...

calculus - For what value of the constant c is the function f continuous on the ...

Maths, continuity - Plz help me out with a solution... f(x) = sin(1/x) when x is...

calculus - Prove that there is a number that is exactly one more than its cube...