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A gold wire 5.90m long and of diameter 0.890 mm carries a current of 1.21A.
A)Find the resistance of this wire.
B)Find the potential difference between its ends.
Can someone please help me I don't know how to answer these questions?
R=p(L/A) 1.21(5.90m/.890mm)
Am i setting this up right?

  • physics - ,

    A) You will have to use the resistivity of gold (which you should look up) to get an answer. The current makes no difference.

    R = (rho)* (L/A) is the correct formula.
    Make sure you use consistent units, such as ohm-cm for rho, cm for length, and cm^2 for area. You did not do that in what you wrote.

    B)Once you have computed R, V = I R

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