Homework Help: physics

Posted by help on Sunday, April 12, 2009 at 3:21pm.

A gold wire 5.90m long and of diameter 0.890 mm carries a current of 1.21A.
A)Find the resistance of this wire.
B)Find the potential difference between its ends.
Can someone please help me I don't know how to answer these questions?
R=p(L/A) 1.21(5.90m/.890mm)
Am i setting this up right?

physics - drwls, Sunday, April 12, 2009 at 4:26pm
A) You will have to use the resistivity of gold (which you should look up) to get an answer. The current makes no difference.

R = (rho)* (L/A) is the correct formula.
Make sure you use consistent units, such as ohm-cm for rho, cm for length, and cm^2 for area. You did not do that in what you wrote.

B)Once you have computed R, V = I R

Answer this Question

Related Questions

college physics - A 4m long copper wire has a diameter of 2mm and carries a ...
physic - The resistivity of gold is at a temperature of 20°C. A gold wire, 1...
Physics - The wire in the drawing carries a current of 14 A. Suppose that a ...
Physics - The wire in the drawing carries a current of 13 A. Suppose that a ...
Physics 2 - The wire in the figure below carries a current of 12 A. Suppose that...
Physics 2 - The wire in the figure below carries a current of 13 A. Suppose that...
Physics 2 - The wire in the figure below carries a current of 13 A. Suppose that...
physics - A copper wire has a circular cross section with a radius of 3.75 mm. ...
physics - A copper wire has a circular cross section with a radius of 3.75 mm. ...
PHYSICS - A long, straight wire lies on a horizontal table and carries a current...

For Further Reading

First Name:
School Subject:
Answer: