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Inorganic chemistry

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What change in coulombs, is required to deposit 0.301 g Cu(s) from a solution of Cu^2+(aq)

  • Inorganic chemistry -

    Let's think it through step by step.

    First convert 0.301g to moles of copper.
    0.301 g /63.5 g/mole = 4.74*10^-3 moles.
    Multiply that by 2 x (Avogadro's number) for the number of electrons.
    Multiply what you get by the number of Coulombs per electron (1.602*10^-19).

    I get 914 C

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