Homework Help: Inorganic chemistry

Posted by Steve on Saturday, April 11, 2009 at 11:22pm.

What change in coulombs, is required to deposit 0.301 g Cu(s) from a solution of Cu^2+(aq)

Inorganic chemistry - drwls, Sunday, April 12, 2009 at 12:46am
Let's think it through step by step.

First convert 0.301g to moles of copper.
0.301 g /63.5 g/mole = 4.74*10^-3 moles.
Multiply that by 2 x (Avogadro's number) for the number of electrons.
Multiply what you get by the number of Coulombs per electron (1.602*10^-19).

I get 914 C

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