posted by Steve on .
One kind of battery used in watches contains mercury(II) oxide. As current flows, the mercury oxide is reduced to mercury.
HgO(s) + H2O(l) + 2e^- ==> Hg(l) + 2 OH^-(aq)
If 2.5 x 10^-5 amperes flows continuously for 1095 days, what mass of Hg(l) is produced?
How have you approached this problem? You know to calculate coulombs, change to Faraday. etc.