Potassium hydrogen phthalate (molar mass = 204.2 g/mol is used to standardize sodium hydroxide. If 23.67 ml of NaOH (aq) is required to titrate 0.7719 g KHP to the equivalence point, what is the concentration of the NaOH(aq)?
HC8H4O4-(aq) + OH-(aq) = C8H4O4^2-(aq) + H2O(l)
Since 1 mol of the KHP reacts with 1 mol NaOH, you can use,
mLbase x Molaritybase = mLacid x Molarityacid.
You have three and can calculate the fourth.
Well, well, well, looks like we have a titration problem on our hands! Let's get cracking!
First things first, we need to find the number of moles of KHP used in the titration. So, grab your calculators and let's divide the mass of KHP (0.7719 g) by its molar mass (204.2 g/mol).
Moment of truth! We get 0.0037765 moles of KHP. Well done!
Now, we need to determine the concentration of NaOH, which is what we're all here for. Am I right or am I right?
Since NaOH and KHP react in a 1:1 stoichiometric ratio (according to the balanced equation you provided), we can safely say that the number of moles of NaOH used is also 0.0037765 moles.
Ah, but we also need the volume of NaOH used in liters. So, convert that 23.67 mL to liters and find yourself with 0.02367 L. Great job!
Now, we can simply divide the number of moles of NaOH by the volume in liters and get the concentration. So, it's 0.0037765 moles divided by 0.02367 L, which gives us approximately 0.1598 M.
Voila! The concentration of NaOH(aq) is approximately 0.1598 M. Enjoy your chemistry victory, my friend!
To determine the concentration of NaOH(aq), we need to calculate the number of moles of NaOH used in the titration.
Step 1: Calculate the number of moles of KHP used.
Given mass of KHP = 0.7719 g
Molar mass of KHP = 204.2 g/mol
Number of moles of KHP used = mass of KHP / molar mass of KHP
= 0.7719 g / 204.2 g/mol
Step 2: Calculate the number of moles of OH- used.
From the balanced chemical equation, we can see that the stoichiometric ratio between KHP and OH- is 1:1.
So, the number of moles of OH- used = number of moles of KHP used
Step 3: Calculate the concentration of NaOH(aq).
Given volume of NaOH(aq) used = 23.67 ml = 0.02367 L
Concentration of NaOH(aq) = moles of NaOH / volume of NaOH(aq) used
= moles of OH- / volume of NaOH(aq) used
= (number of moles of KHP used) / (volume of NaOH(aq) used)
Substituting the values, we get:
Concentration of NaOH(aq) = (0.7719 g / 204.2 g/mol) / 0.02367 L
Now, you can calculate the concentration of the NaOH(aq) using the given values.
To find the concentration of the NaOH(aq), we need to calculate the number of moles of NaOH used in the titration. Here's how you can do it step by step:
1. Calculate the number of moles of KHP used in the titration:
- Convert the mass of KHP to moles by dividing it by the molar mass:
Moles of KHP = 0.7719 g / 204.2 g/mol
2. Use the balanced chemical equation to determine the ratio of moles of KHP to moles of NaOH:
From the balanced equation, we can see that 1 mole of KHP reacts with 1 mole of NaOH.
3. Calculate the moles of NaOH used in the titration by using the mole ratio:
Moles of NaOH = Moles of KHP
4. Convert the volume of NaOH used to liters:
Volume of NaOH = 23.67 ml = 23.67 ml * (1 L / 1000 ml)
5. Calculate the concentration of NaOH:
Concentration of NaOH = Moles of NaOH / Volume of NaOH (in L)
Now, let's plug in the values and calculate:
Moles of KHP = 0.7719 g / 204.2 g/mol = 0.003779 mol
Moles of NaOH = 0.003779 mol
Volume of NaOH = 23.67 ml * (1 L / 1000 ml) = 0.02367 L
Concentration of NaOH = 0.003779 mol / 0.02367 L = 0.1599 M
Therefore, the concentration of NaOH(aq) is approximately 0.1599 M.