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August 20, 2014

August 20, 2014

Posted by **adam** on Saturday, April 11, 2009 at 7:05pm.

f(x)= 4x^3+ab^2+bx+k

where a, b, k, are constants. The function f has a local minimum at x=-2

A. Fine the vales of a and b

B. If you integrate f(x) dx =32 from o to 1, what is the value of K?

- calculus -
**drwls**, Saturday, April 11, 2009 at 7:37pmI assume you typed the question wrong and meant f(x)= 4x^3 +ax^2 +bx+ k

The derivative f'(x) must be zero at x = -2, so

12x^2 + 2ax + b = 0 at x=2

48 -4a +b = 0

You need more information to be able to calculate both a and b.

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