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December 18, 2014

December 18, 2014

Posted by **Shannon** on Saturday, April 11, 2009 at 5:21pm.

2. Trains A and B are traveling in the same direction on parallel tracks. 2. Train A is travelling at 100 miles per hour and train B is traveling at 125 miles per hour. Train A passes a station at 5:10 A.M. If train B passes the same station at 5:22 A.M, at what time will train B catch up to train A?

100(t) + 20 = 125(t)

100t + 20 = 125t

25t = 20

t = 20/25 = 4/5 hr X 60 = 48 min

5:22 + 48 = 6:10 they pass each other

Proof

100(4/5) + 20 = 125(4/5)

80 + 20 = 4(25)

100 = 100

- Algebra -
**Damon**, Saturday, April 11, 2009 at 5:45pmAgree

- Algebra -
**Shannon**, Saturday, April 11, 2009 at 6:17pmThank you!!!

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