Posted by **Renee =D** on Saturday, April 11, 2009 at 7:29am.

The mass of the Moon is 7.35x10 to the 22nd Kg. At some point between the Earth and the Moon, the for of Earth's gravitational attraction on an object is cancelled by the Moon's force of gravitational attraction. If the distance between Earth and the Moon (centre to centre) is 3.84x10 to the 5th km, calculate where this will occur, relative to Earth.

- Physics -
**drwls**, Saturday, April 11, 2009 at 7:52am
Let X be the distance from Earth. You will need the mass of the Earth also. Call it M and the moon's mass m.

Let D = 3.84*10^5 km

For the forces to be equal,

G M/x^2 = G m/(D-x)^2

G (the universal law of gravity constant) cancels out.

Solve for x/D in terms of M/m

[(D-x)/x]^2 = (D/x -1]^2 = m/M

D/x -1 = sqrt (m/M)

## Answer this Question

## Related Questions

- Physics - The mass of the Moon is 7.35 x 10^22 kg. At some point between Earth ...
- physics - Which of the following correctly describe the gravitational attraction...
- Physics - When a spacecraft travels from the Earth to the Moon, both the Earth ...
- physics - In the Earth–Moon system, there is a point where the gravitational ...
- physics help please! - A spacecraft is on a journey to the moon. At what point...
- physics - A spacecraft is on a journey to the moon. At what point, as measured ...
- physics - Suppose that the attraction between the moon and the earth were due to...
- Physics - The Moon causes tides because the gravitational force it exerts ...
- physics - When a spacecraft travels from Earth to the Moon, the gravitational ...
- Calculus Physics - Imagine a spaceship on its way to the moon from the earth. ...