Posted by Renee =D on Saturday, April 11, 2009 at 7:29am.
Let X be the distance from Earth. You will need the mass of the Earth also. Call it M and the moon's mass m.
Let D = 3.84*10^5 km
For the forces to be equal,
G M/x^2 = G m/(D-x)^2
G (the universal law of gravity constant) cancels out.
Solve for x/D in terms of M/m
[(D-x)/x]^2 = (D/x -1]^2 = m/M
D/x -1 = sqrt (m/M)
Related Questions
physics - A spacecraft is on a journey to the moon. At what point, as measured ...
physics help please! - A spacecraft is on a journey to the moon. At what point...
physics - Calculate the magnitudes of the gravitational forces exerted on the ...
Physics - The Moon causes tides because the gravitational force it exerts ...
Physics - The mass of the Moon is 7.35 x 10^22 kg. At some point between Earth ...
Physics - A satellite is placed between the Earth and the Moon, along a straight...
WSU PHY - The Moon causes tides because the gravitational force it exerts ...
physics - Suppose that the attraction between the moon and the earth were due to...
physics - The physics of energy and Earth's moon as a satellite. The moon is...
Physics - The Moon orbits the Earth at a distance of 3.85 x 108 m. Assume that ...
For Further Reading