Posted by **Angie** on Friday, April 10, 2009 at 10:06pm.

How are you supposed to write an equation for the line that is parallel to the given line and that passes through the given point? For ex., what do you do for y = 3/4 x - 9, (-8,-18)?

- Math -
**Reiny**, Friday, April 10, 2009 at 10:57pm
since the line is parallel to the old one, the slope of the new one must be the same as the slope of the old one.

that is,

the new equation must be

y = (3/4)x + b

plug in the given point to find b,

put b back in the above equation and you are done.

- Math -
**Angie**, Saturday, April 11, 2009 at 12:08pm
thanks..in your opinion, is the way you did easier than doing it with point-slope form?

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