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February 1, 2015

February 1, 2015

Posted by **Brad** on Friday, April 10, 2009 at 9:56pm.

I realize it is 4/C(52,5), but what are the combinations for the numerator?

- MATH -
**Reiny**, Friday, April 10, 2009 at 11:59pmDon't assume everybody knows what a royal flush is, I had to look it up

http://en.wikipedia.org/wiki/Hand_rankings#Straight_flush

There are 4 possible royal flushes.

the number of ways to choose any 5 cards

= C(52,5)

so the prob of a royal flush = 4/C(52,5)

= 4/2598960

= 1/649740

- MATH -
**chloe x**, Saturday, April 11, 2009 at 7:22amthts sounds sooooooooooooooooooo hard .

i'm glad i don't have 2 do tht !!

lv u xxxxxxx

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