Posted by **Anonymous** on Friday, April 10, 2009 at 8:17pm.

The sum of the ages of the three Romano brothers is 63. If their ages can be represented as consecutive integers, what is he age of the middel brother?

- math -
**Reiny**, Friday, April 10, 2009 at 11:52pm
let the middle brother's age be x

then the oldest is x+1

and the youngest is x-1

x-1 + x + x+1 = 63

solve for x to get middle brother's age.

- math -
**drwls**, Saturday, April 11, 2009 at 4:29pm
63 is three times the average age (which is that of the middle brother), so that age much be 21. The ages of all three are therefore 20, 21 and 22.

## Answer this Question

## Related Questions

- Algebra - The ages of three brothers are three consecutive even integers. If ...
- Algebra - The ages of three brothers are consecutive even integers. Three times ...
- Math - In the Ambrose family, the ages of the three children are three ...
- Math - 1. The sum of the ages of two brothers is 46. The younger brother is 10 ...
- Math - When Juan divides each of five consecutive integers by his age , the sum ...
- Math - The sum of the ages of a brother and sister is 27. If four times the ...
- early childhood education - your budget allows you to purchase only one math ...
- algebra - The present ages in years of four cousins are consecutive multiples of...
- business - Your budjet allows you to purchase only one math software package for...
- ALG 2 PLZ PLZ HELP - 1.)The product of 14 and n is -28. Write the algebraic ...

More Related Questions