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October 23, 2014

Homework Help: Physics

Posted by LeRoy on Friday, April 10, 2009 at 2:27pm.

Double check this for me:

A player kicks a football with an initial velocity of 3.00 m/s at an angle of 60.0* above the horizontal. What is the horizontal distance traveled by the football?

s = vi*t + (1/2)(a)(t2)
0 = 3sin(30)t + 0.5(-9.8)(t2)
t = 0.306 seconds

x = vt there is no horizontal acceleration
x = 3cos(30)(0.306 seconds)
x = 0.795011321 meters
x = 0.795 meters

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