Posted by candy on Friday, April 10, 2009 at 9:57am.
If you mixed solid sodium carbonate with HCl (aq) the sodium carbonate dissolves in the water solution of acid, becoming (aq).
Now if you use CaCO3 instead, it is not soluble in the water, so what happens is the acid attacks the ionic structure of the chalk, breaking it apart. Yes, I would put CaCO3 (s) on the left side.
and an additional note: By adding the CaCO3 (s) on the left, you have to add Ca+2 on the right to balance charge.
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