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December 19, 2014

December 19, 2014

Posted by **alana** on Thursday, April 9, 2009 at 3:32pm.

x^2+y^2+z^2=9

above the xy plane, and outside the cone

z=2*sqrt(x^2+y^2)??

- math -
**Count Iblis**, Thursday, April 9, 2009 at 5:16pmIn spherical coordinates the region outside the cone and above the xy plane corresponds to theta (the angle between the z-axis and the position vector)between

arctan(1/2) and pi/2.

So, the volume is:

Integral over phi from 0 to 2pi

Integral over theta from atn(1/2) to pi/2

Integral over r from 0 to 3

dr dtheta dphi r^2 sin(theta)

- math -
**Ellen**, Tuesday, April 17, 2012 at 6:34pmThis is incorrect

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