Wednesday

July 30, 2014

July 30, 2014

Posted by **tina** on Thursday, April 9, 2009 at 10:43am.

- math -
**Damon**, Thursday, April 9, 2009 at 11:05amMake a table

--B1 B2 B3 B4 B5 B6 B7

J1 --y- y- n- n- n- n-

J2 y -- y- n- n- n- n-

J3 y y- -- n- n- n- n-

J4 n n- n- -- n- n- n-

J5 n n- n- n- -- n- n-

J6 n n- n- n- n- -- n-

J7 n n- n- n- n- n- --

The diagonal elemnts are not part of our possibilities because they can no both finish in the same position.

That leaves us with 42 possible outcomes

of those 42, six are y which means six of the 42 outcomes have both B and J in the first 3 places.

6/42 =3/21

- Trying to clean up table -
**Damon**, Thursday, April 9, 2009 at 11:09amMake a table

--b1 b2 b3 b4 b5 b6 b7

J1 --y- y- n- n- n- n-

J2 y -- y- n- n- n- n-

J3 y y- -- n- n- n- n-

J4 n n- n- -- n- n- n-

J5 n n- n- n- -- n- n-

J6 n n- n- n- n- -- n-

J7 n n- n- n- n- n- --

The diagonal elements are not part of our possibilities because they can no both finish in the same position.

That leaves us with 42 possible outcomes

of those 42, six are y which means six of the 42 outcomes have both B and J in the first 3 places.

6/42 =3/21

- Oh well -
**Damon**, Thursday, April 9, 2009 at 11:12amI can not get columns to line up no matter what I do using -- or - for spacers

you have 7 rows and seven columns

the diagonals, marked with -- are out because J and B can not finish in the same place.

The y solutions are the good ones.

The n solutions are no good.

- math -
**tina**, Thursday, April 9, 2009 at 11:43amthere are 3 people not only 2

- math -
**tina**, Thursday, April 9, 2009 at 11:47amyou left out morgan

- math -
**Reiny**, Thursday, April 9, 2009 at 1:30pmthe number of ways for J, M and B and 5 others can be arranged is

3!5!.

The number of ways all 8 can be arranged is 8!

so the prob that they will be the first 3 finishers

= 3!5!/8! = 1/56

but you asked for the odds

odds of some event = prob the event will happen : prob the event will not happen

= (1/56):(55/56)

= 1 : 55

- math -
**megan**, Wednesday, April 25, 2012 at 10:35pmFor Jerome the chances are 3/8 (if all of the runners had equal ability). For Morgan, after Jerome had gotten first (let's say he did) then his chances would be 2/7. And for Bly his chances are 1/6. Now you have got to multiply them all together.

(3/8) (2/6) (1/6) = 1/56

i feel like this is the easy way of doing it...

**Related Questions**

pre algebra - Jerome, Morgan, and Bly compete in a 10-kilometer race with 5 ...

Ball Charter Math - Julia arrived 20 minutes before the race began. She started ...

math - julie arrived 20 minutes before the race began. she started right on time...

Math - A race track tote board has the odds for a horse listed as 5 to 3. Tote ...

math number story - julie arrived 20 minutes before the race began she started ...

math - rich ran a 5 kilometer race how many meters is five kilometer

physics - 2 runners accelerate from rest to their top speeds. The 1st runner pat...

physics - A hare and a tortoise compete in a race over a course 4.90 km long. ...

Physics - A hare and a tortoise compete in a race over a course 1.20 km long. ...

math - you competed in a 3.9 kilometer race you finished the race in 0.4 hours. ...