Posted by nirali on Thursday, April 9, 2009 at 5:29am.
In the isothermal case, P*V = constant = P1 V1.
The work done is Integral P dV
= Integral (P1 V1)dV/V
= P1 V1 ln(V2/V1)
In the adiabatic case,
P*V^(5/3) = constant
(for monatomic gases)
The work is once again Integral P dV, but you get a different answer.
Work = [P1*V1^(5/3)]*Integral dV/V^(5/3)
hey drwl thank u so much. but i didnt get right answer for work done. do i hav to convert pressure to pascal for work done? cn u help me?
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