Posted by **nirali** on Thursday, April 9, 2009 at 5:29am.

An ideal monatomic gas initially has a temperature of 333 K and a pressure of 7.15 atm. It is to expand from volume 581 cm3 to volume 1360 cm3. If the expansion is isothermal, what are (a) the final pressure (in atm) and (b) the work done by the gas? If, instead, the expansion is adiabatic, what are (c) the final pressure (in atm) and (d) the work done by the gas?

- physics- vry urgent -
**drwls**, Thursday, April 9, 2009 at 5:47am
In the isothermal case, P*V = constant = P1 V1.

The work done is Integral P dV

= Integral (P1 V1)dV/V

= P1 V1 ln(V2/V1)

In the adiabatic case,

P*V^(5/3) = constant

(for monatomic gases)

The work is once again Integral P dV, but you get a different answer.

Work = [P1*V1^(5/3)]*Integral dV/V^(5/3)

- physics- vry urgent -
**nirali**, Friday, April 10, 2009 at 12:02am
hey drwl thank u so much. but i didn't get right answer for work done. do i hav to convert pressure to pascal for work done? cn u help me?

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