Posted by Mary on Wednesday, April 8, 2009 at 10:48pm.
Solve:
4 + 5x < 29
5x < 4 +29
5x < 4 +29
5x=25
Solution set is xx < 5
4x+5y=7
5x4y=5
The lines are parallel am I right

math  drwls, Wednesday, April 8, 2009 at 11:18pm
5x < 25; therefore x < 5
Your "solution set" is wrong.
Your last pair of equations seems to go with a different question. The lines are NOT parallel. They are perpendicular.

math  Reiny, Wednesday, April 8, 2009 at 11:19pm
I believe you asked the same question yesterday, at least the second one is the same.
Don't you go back to see if your questions get answered?
http://www.jiskha.com/display.cgi?id=1239151226
for the first one, from ...
5x < 4 +29
5x < 25
x < 5
so {x│x < 5}
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