Solve:
4 + 5x < 29
5x < 4 +29
5x < -4 +29
5x=-25
Solution set is x|x < -5
4x+5y=7
5x-4y=5
The lines are parallel am I right
5x < 25; therefore x < 5
Your "solution set" is wrong.
Your last pair of equations seems to go with a different question. The lines are NOT parallel. They are perpendicular.
I believe you asked the same question yesterday, at least the second one is the same.
Don't you go back to see if your questions get answered?
http://www.jiskha.com/display.cgi?id=1239151226
for the first one, from ...
5x < -4 +29
5x < 25
x < 5
so {x│x < 5}
To solve the inequality 4 + 5x < 29:
1. Start by subtracting 4 from both sides of the inequality:
4 + 5x - 4 < 29 - 4
5x < 25
2. Next, divide both sides of the inequality by 5 to isolate the variable x:
(5/5)x < 25/5
x < 5
Therefore, the solution set for the inequality is x < 5.
For the system of equations 4x + 5y = 7 and 5x - 4y = 5:
To determine if the lines represented by the equations are parallel, we need to check the slopes of both lines.
1. Rewrite the equations in slope-intercept form y = mx + b (where m is the slope):
4x + 5y = 7 -> 5y = -4x + 7 -> y = (-4/5)x + 7/5
5x - 4y = 5 -> -4y = -5x + 5 -> y = (5/4)x - 5/4
2. Comparing the coefficients, we see that the slope of the first line is -4/5 and the slope of the second line is 5/4.
Since the slopes are not equal, the lines represented by the equations are not parallel.