Friday

August 22, 2014

August 22, 2014

Posted by **sweety** on Wednesday, April 8, 2009 at 9:21pm.

- physics -
**Count Iblis**, Wednesday, April 8, 2009 at 9:40pmStart with part c). In case of an ideal gas, the internal energy only depends on temperature. In case of a monoatomic gas we have:

E = 3/2 N k T

here k is Boltzmann's constant and N is given as

N = 7.1 mol = 4.276*10^24

So, we have:

E = 88.55 J/K T

If the temperature is raised by 15 , then the increase in E is thus 1328 J.

The change in internal eenrgy is also equal to the heat abosorbed minus the work done by the gas. An adiabatic change means, by definition, that the absorbed heat is zero. So, the work done by the gas is minus 1328 J.

**Related Questions**

physics - The temperature of 7.10 mol of an ideal monatomic gas is raised 15.0 K...

thermal physics - The temperature of 7.10 mol of an ideal monatomic gas is ...

physics - The temperature of 7.10 mol of an ideal monatomic gas is raised 15.0 K...

physics - The temperature of 2.10 mol of an ideal monatomic gas is raised 17.0 K...

physics - The temperature of 4.60 mol of an ideal monatomic gas is raised 15.0 K...

physics - The temperature of 4.60 mol of an ideal monatomic gas is raised 15.0 K...

physics - The temperature of 4.60 mol of an ideal monatomic gas is raised 15.0 K...

physics - The temperature of 6.80 mol of an ideal monatomic gas is raised 12.0 K...

physics - We start with 5.00 moles of an ideal monatomic gas with an initial ...

Physics - The temperature of a monatomic ideal gas remains constant during a ...