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September 30, 2014

September 30, 2014

Posted by **sweety** on Wednesday, April 8, 2009 at 9:21pm.

- physics -
**Count Iblis**, Wednesday, April 8, 2009 at 9:40pmStart with part c). In case of an ideal gas, the internal energy only depends on temperature. In case of a monoatomic gas we have:

E = 3/2 N k T

here k is Boltzmann's constant and N is given as

N = 7.1 mol = 4.276*10^24

So, we have:

E = 88.55 J/K T

If the temperature is raised by 15 , then the increase in E is thus 1328 J.

The change in internal eenrgy is also equal to the heat abosorbed minus the work done by the gas. An adiabatic change means, by definition, that the absorbed heat is zero. So, the work done by the gas is minus 1328 J.

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