Posted by **sweety** on Wednesday, April 8, 2009 at 9:21pm.

The temperature of 7.10 mol of an ideal monatomic gas is raised 15.0 K in an adiabatic process. What are (a) the work W done by the gas, (b) the energy transferred as heat Q, (c) the change ÄEint in internal energy of the gas, and (d) the change ÄK in the average kinetic energy per atom?

- physics -
**Count Iblis**, Wednesday, April 8, 2009 at 9:40pm
Start with part c). In case of an ideal gas, the internal energy only depends on temperature. In case of a monoatomic gas we have:

E = 3/2 N k T

here k is Boltzmann's constant and N is given as

N = 7.1 mol = 4.276*10^24

So, we have:

E = 88.55 J/K T

If the temperature is raised by 15 , then the increase in E is thus 1328 J.

The change in internal eenrgy is also equal to the heat abosorbed minus the work done by the gas. An adiabatic change means, by definition, that the absorbed heat is zero. So, the work done by the gas is minus 1328 J.

## Answer This Question

## Related Questions

- physics - The temperature of 7.10 mol of an ideal monatomic gas is raised 15.0 K...
- thermal physics - The temperature of 7.10 mol of an ideal monatomic gas is ...
- physics - The temperature of 2.10 mol of an ideal monatomic gas is raised 17.0 K...
- physics - The temperature of 4.60 mol of an ideal monatomic gas is raised 15.0 K...
- physics - The temperature of 4.60 mol of an ideal monatomic gas is raised 15.0 K...
- physics - The temperature of 4.60 mol of an ideal monatomic gas is raised 15.0 K...
- physics - The temperature of 6.80 mol of an ideal monatomic gas is raised 12.0 K...
- physics - The temperature of 7.10 mol of an ideal monatomic gas is raised 15.0 K...
- Physics - Suppose that 4.7 moles of a monatomic ideal gas (atomic mass = 8.5 × ...
- Physics - A tank with a constant volume of 3.44 m3 contains 14 moles of a ...

More Related Questions