November 27, 2015

Homework Help: Chemistry

Posted by Kathryn on Tuesday, April 7, 2009 at 10:27pm.

I am beyond desperate. I do not understand how to calculate heat change at all and I have been looking online and reading my book for the last three hours. Below is posted a problem. It would be amazing if someone could work through it and explain each step they are doing and why they are doing it.

Calculate the heat change for the formation of lead(IV) chloride by the reaction of lead(II) chloride with chlorine
PbCl2(s) + Cl2(g) -> PbCl4(l) H=?
Use the following thermochemical equations:
Pb(s) + 2Cl2(g) -> PbCl4(l) h= -329.2kj
Pb(s) + Cl2(g) -> PbCl2(s) h= -359.4kj

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