Posted by **Caroline** on Tuesday, April 7, 2009 at 8:46pm.

Please help with this problem!

Planet Pemdas is a perfect sphere that does not rotate. If a rocket flies in a path following the circumference of Pemdas, and maintains a constant altitude of 25,000 feet above the surface for one orbit, how many more feet than the planet's circumference is the path of the rocket? Express the answer to the nearest thousand feet.

- Math -
**Chemistry**, Tuesday, April 7, 2009 at 9:09pm
radius increasses by 25000 solve for dimater then solve for circumference i think

- Math -
**Reiny**, Tuesday, April 7, 2009 at 10:41pm
circumf of planet = 2pi(r)

circumf of path of rocket = 2pi(r+25000)

= 2p(r) + 2pi(25000)

so the increase is 2pi(25000)

(I am sure the people of Pemdas would not use a medieval unit of measurement as the "foot")

- Math -
**Caroline [:**, Wednesday, April 8, 2009 at 6:40am
Thank you SO much!!!

[:

## Answer This Question

## Related Questions

- MATH MULTIPLICATION!!! - PLEASE HELP ME SOLVE THIS PROBLEM: 4((3x-6)/(6x+2))^3...
- Math - 8*2sq+7*(4+1)= ? Can someone explain to me what to after the parenthesis...
- algebra1 - A)a plane flies at the height of 1800 feet directly over 150-foot-...
- Math - A pilot flies in a straight path for 1 h 30 min. She then makes a course ...
- math - A pilot flies in a straight path for 1 h 30 min. She then makes a course ...
- algebra - making linear equation from word problem An airspeed indicator on ...
- math - I am suppose to solve for the following prolbem using PEMDAS _ / _ * _ + ...
- precalculus - A pilot flies in a straight path for 2 h 30 min. She then makes a ...
- math,correction,plz - Evaluate (15-5)/[((12)/(2*2))-2] my answer that i keep ...
- math (altitude) - An airplane flying at an altitude of 31,000 feet descends at a...

More Related Questions