Wednesday

July 23, 2014

July 23, 2014

Posted by **Marissa** on Tuesday, April 7, 2009 at 1:25am.

THANKS!

What is the minimum thickness of coating which should be placed on a lens in order to minimize reflection of 531 nm light? The index of refraction of the coating material is 1.32 and the index of the glass is 1.57.

- Physics -
**drwls**, Tuesday, April 7, 2009 at 2:30amRead "single layer reflection coatings" at

http://en.wikipedia.org/wiki/Anti-reflective_coating#Single-layer_interference_coatings

You need 1/4 wavelength thickness at a refractive index of 1.32

At 531 nm and index 1.32, the wavelength of light is 531/1.32 = 412 nm

The coating thickness should be 1/4 of that

- Physics -
**Marissa**, Tuesday, April 7, 2009 at 12:30pmthat's what i thought, too. but it's not.

2n(material)t= m*(wavelength/2)

going from a medium with higher n to lower n, you divide the wavelength by 2.

thanks for the help, though. i eventually figured it out!

**Related Questions**

calculus - I am working on this problem and having some trouble. We're supposed ...

math - I'm working on some review problems in Math and having trouble on the ...

math - i am having a hard time with factoring i have read what is here but am ...

physics bobpursly help still having trouble - A satellite in a circular orbit ...

math - I'm having issues with understanding exactly how Expected Values work, I ...

Calc help - find the area of the region enclosed by y=e^2x, y=e^5x, and x=1. i ...

physics - i have to build a catapult that will fire a projectile that will pass ...

Algebra 1 - I'm having trouble solving x=2(x-1)+6 I understand but I get ...

AP Chemistry - i'm having trouble balancing the redox reaction for the iodine ...

Chemistry - Dr.Bob222, I've been attempting the problem I posted previously ...