Posted by claire on Monday, April 6, 2009 at 11:45pm.
Start with (x^3 - 8)(x^3 + 8).
One factor of x^3 -8 is (x-2). The other is(x^3 -8)/(x-2) = x^2 + 2x + 4.
The other factors are complex numbers, such as x + 2i. I assume they are not wanted.
You are left with
(x-2)(x^2 + 2x + 4)(x^3 + 8)
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