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July 29, 2014

July 29, 2014

Posted by **claire** on Monday, April 6, 2009 at 11:45pm.

x^6-64

How do I know if i'm supposed to use the difference of two squares, or the difference of cubes?

- math help -
**drwls**, Tuesday, April 7, 2009 at 6:58amStart with (x^3 - 8)(x^3 + 8).

One factor of x^3 -8 is (x-2). The other is(x^3 -8)/(x-2) = x^2 + 2x + 4.

The other factors are complex numbers, such as x + 2i. I assume they are not wanted.

You are left with

(x-2)(x^2 + 2x + 4)(x^3 + 8)

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