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January 30, 2015

Posted by **nini** on Monday, April 6, 2009 at 9:28pm.

1.) 8a^2+12ab-3b^2-2ab

2.) x^2+5x+7x+35

- Gr.10 Math!!!! urgent -
**Riley**, Monday, April 6, 2009 at 9:32pm2) first rearrang terms to solve

x^2+5x+7x+35

x^2+12x+35

now what two numbers added together make 12 and multiplied make 30? those are your factors to go in the parentheses. Like this:

x^2+12x+35

(x+?)(x+?) this is the answer then.

- Gr.10 Math!!!! urgent -
**nini**, Monday, April 6, 2009 at 9:37pmthnkss, 1.)??

- Gr.10 Math!!!! urgent -
**Riley**, Monday, April 6, 2009 at 9:39pmThe first one works like this:

8a^2+12ab-3b^2-2ab

take the first two terms and notice the common multiple of 4 and a. they become

4a(2a+3b)

Now take the last two terms and notice the common multiple of b. they become:

-b(2a+3b)

Now see the common factor in the parentheses? (2a+3b)

This comes out in front to become:

(2a+3b)(4a-b)

Multiply together to check your answer and you will see it is correct.

- Gr.10 Math!!!! urgent -
**Riley**, Monday, April 6, 2009 at 9:39pmDid that make sense? were you able to solve #1 and understand #2?

- Gr.10 Math!!!! urgent -
**nini**, Monday, April 6, 2009 at 9:41pmfor 1.) what formula are u using though?

- Gr.10 Math!!!! urgent -
**Riley**, Monday, April 6, 2009 at 9:43pmno set formula. Just remember in problems with more than one variable first factor the first two terms and then the second two terms and look for a common factor(s) which will usually appear in the parentheses or outside. Then multiply this by the remaining terms to get your answer. Always multiply back to out to check your work.

try this problem to see if you understand:

4a^2+2ab-b^2-2ab

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