Posted by nini on Monday, April 6, 2009 at 9:28pm.
Factor by Grouping. PLEASE SHOW ME THE STEPS!
1.) 8a^2+12ab3b^22ab
2.) x^2+5x+7x+35

Gr.10 Math!!!! urgent  Riley, Monday, April 6, 2009 at 9:32pm
2) first rearrang terms to solve
x^2+5x+7x+35
x^2+12x+35
now what two numbers added together make 12 and multiplied make 30? those are your factors to go in the parentheses. Like this:
x^2+12x+35
(x+?)(x+?) this is the answer then. 
Gr.10 Math!!!! urgent  nini, Monday, April 6, 2009 at 9:37pm
thnkss, 1.)??

Gr.10 Math!!!! urgent  Riley, Monday, April 6, 2009 at 9:39pm
The first one works like this:
8a^2+12ab3b^22ab
take the first two terms and notice the common multiple of 4 and a. they become
4a(2a+3b)
Now take the last two terms and notice the common multiple of b. they become:
b(2a+3b)
Now see the common factor in the parentheses? (2a+3b)
This comes out in front to become:
(2a+3b)(4ab)
Multiply together to check your answer and you will see it is correct. 
Gr.10 Math!!!! urgent  Riley, Monday, April 6, 2009 at 9:39pm
Did that make sense? were you able to solve #1 and understand #2?

Gr.10 Math!!!! urgent  nini, Monday, April 6, 2009 at 9:41pm
for 1.) what formula are u using though?

Gr.10 Math!!!! urgent  Riley, Monday, April 6, 2009 at 9:43pm
no set formula. Just remember in problems with more than one variable first factor the first two terms and then the second two terms and look for a common factor(s) which will usually appear in the parentheses or outside. Then multiply this by the remaining terms to get your answer. Always multiply back to out to check your work.
try this problem to see if you understand:
4a^2+2abb^22ab