How do I sketch the graph of this equation?
h=-08t2 + 10t
What is h at t=0?
What is h at t=1
what is h at t=-1
what is h at t=10? -10
how to do algebra
To sketch the graph of the equation h = -0.8t^2 + 10t, you can follow these steps:
Step 1: Determine the axes and scale
Decide which axis represents the values of t (the input) and which axis represents h (the output). Choose a suitable scale for both axes to accommodate the range of values.
Step 2: Identify intercepts
To find the y-intercept (h-intercept), substitute t = 0 into the equation and solve for h. This will give you a point on the vertical axis where the graph intersects.
Step 3: Find the vertex
To determine the x-coordinate of the vertex, use the formula -b/(2a), where the equation is in the form ax^2 + bx + c. In this case, a = -0.8 and b = 10. Substitute these values into the formula to find the t-value of the vertex. Then calculate the corresponding h-value by substituting the t-value into the equation. This will give you the coordinates of the vertex.
Step 4: Plot additional points
Choose some additional values for t, substitute them into the equation, and calculate the corresponding h-values. Plot these points on the graph.
Step 5: Sketch the curve
Connect the plotted points smoothly, following the general shape of a quadratic curve. The graph of a quadratic equation is usually a parabola.
Step 6: Label the axes and add any necessary information
Label the t-axis and h-axis. If there are any important features or key points to note on the graph, such as the vertex or intercepts, label them accordingly.
By following these steps, you should be able to sketch the graph of the given equation h = -0.8t^2 + 10t.