How many molecules of Hydrogen gas formed when 48.7 grams of sodium added to water
write the balanced equation:
2Na+2HOH>>2NaOH + H2
which means find the moles of Na used (in 48.7g), divide those moles by two, and that is the moles of H2. For molecules, then multiply that by Alvarado's number
How would you calculate the numher of nanometers in 8.1 cm?
na:22.9 g
h2:2(1.008)=
To determine how many molecules of hydrogen gas are formed when 48.7 grams of sodium is added to water, we need to follow a few steps.
Step 1: Calculate the moles of sodium.
The molar mass of sodium (Na) is 22.99 g/mol. To find the moles of sodium, divide the given mass (48.7 g) by the molar mass:
Moles of sodium = 48.7 g / 22.99 g/mol
Step 2: Determine the moles of hydrogen gas formed.
The balanced chemical equation for the reaction between sodium and water is:
2 Na + 2 H₂O → 2 NaOH + H₂
From the equation, we see that 2 moles of sodium react to form 1 mole of hydrogen gas. Therefore, the moles of hydrogen gas formed will be half of the moles of sodium:
Moles of hydrogen gas = (Moles of sodium) / 2
Step 3: Convert moles of hydrogen gas to molecules.
One mole of any substance contains Avogadro's number (6.022 x 10^23) of particles, which includes molecules. Therefore, to convert moles of hydrogen gas to molecules, multiply the moles by Avogadro's number:
Molecules of hydrogen gas = (Moles of hydrogen gas) x Avogadro's number
By following these steps and performing the calculations, you can determine the number of molecules of hydrogen gas formed when 48.7 grams of sodium is added to water.