Posted by KC on Monday, April 6, 2009 at 4:10pm.
work done=2.5*3 + 2*3*4 I get more than you. You did the accelerating force only, you have to add the force working against friction
Help!I'm really lost on this one.
correction: I mistyped the distance on friction.
Workdone=2.5*4+2*3*4 joules.
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