What mass of sodium cholride is produced when chlorine reacts with 0.29 grams of sodium iodide?

To determine the mass of sodium chloride produced, we need to find the balanced chemical equation for the reaction between chlorine (Cl2) and sodium iodide (NaI). The balanced equation is as follows:

2NaI + Cl2 -> 2NaCl + I2

From the balanced equation, we can see that two moles of sodium iodide (NaI) react with one mole of chlorine gas (Cl2), producing two moles of sodium chloride (NaCl) and one mole of iodine (I2).

Now, let's calculate the molar mass of sodium iodide (NaI) and chlorine (Cl2):

NaI: Sodium (Na) has a molar mass of 22.99 grams/mole, and iodine (I) has a molar mass of 126.90 grams/mole.
Molar mass of NaI = (22.99 grams/mole) + (126.90 grams/mole) = 149.89 grams/mole

Cl2: Chlorine (Cl) has a molar mass of 35.45 grams/mole. Since we have just one mole of chlorine gas, we don't need to perform any calculations.

Next, let's calculate the number of moles of sodium iodide (NaI) using the given mass:

Given mass of sodium iodide = 0.29 grams
Moles of NaI = Given mass / Molar mass of NaI
Moles of NaI = 0.29 grams / 149.89 grams/mole ≈ 0.001933 moles

Since the balanced equation tells us that 2 moles of NaI react with 1 mole of Cl2 and produce 2 moles of NaCl, we can use this ratio to determine the number of moles of NaCl produced:

Moles of NaCl = (Moles of NaI) × (2 moles of NaCl / 2 moles of NaI)
Moles of NaCl = 0.001933 moles × (2/2) = 0.001933 moles

Lastly, let's calculate the mass of sodium chloride (NaCl) produced:

Mass of NaCl = (Moles of NaCl) × (Molar mass of NaCl)
Mass of NaCl = 0.001933 moles × (22.99 grams/mole + 35.45 grams/mole) ≈ 0.116 grams

Therefore, approximately 0.116 grams of sodium chloride is produced when chlorine reacts with 0.29 grams of sodium iodide.

To determine the mass of sodium chloride produced when chlorine reacts with sodium iodide, we first need to write a balanced chemical equation for the reaction.

The balanced equation for the reaction between chlorine (Cl₂) and sodium iodide (NaI) is:

Cl₂ + 2NaI -> 2NaCl + I₂

According to the balanced equation, 1 mole of chlorine reacts with 2 moles of sodium iodide to produce 2 moles of sodium chloride and 1 mole of iodine.

Now, we need to calculate the number of moles of sodium iodide (NaI) given the mass of 0.29 grams. To do this, we can use the molar mass of NaI.

The molar mass of sodium iodide (NaI) is:

NaI = 22.99 g/mol (sodium) + 126.9 g/mol (iodine) = 149.89 g/mol

Now we can calculate the number of moles of sodium iodide (NaI):

moles of NaI = mass / molar mass
= 0.29 g / 149.89 g/mol
≈ 0.00193 moles

According to the balanced equation, the ratio between sodium iodide (NaI) and sodium chloride (NaCl) is 2:2 (or 1:1). Therefore, the number of moles of sodium chloride produced will also be 0.00193 moles.

Now we can calculate the mass of sodium chloride produced using the molar mass of NaCl:

The molar mass of sodium chloride (NaCl) is:

NaCl = 22.99 g/mol (sodium) + 35.45 g/mol (chlorine) = 58.44 g/mol

mass of NaCl = moles of NaCl × molar mass of NaCl
= 0.00193 moles × 58.44 g/mol
≈ 0.112 grams

Therefore, when 0.29 grams of sodium iodide reacts with chlorine, approximately 0.112 grams of sodium chloride will be produced.

Balance the equation:

2NaI+ Cl2>>>2NaCl +I2
so two moles of sodium iodide react with one mole of chlorine.

How many moles of sodium Iodide is .29grams?
divide that by 2 to get moles of Cl2.
now multiply by the mole mass of Cl2 to get the mass of chlorine.