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3unit maths

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Find the equation of the chord of the parabola joining the points with parameters
(a)1 and -3 on x=2t, y=t^2
(b)1/2 and 2 on x=4t, y=2t^2
(c)-1 and -2 on x=t, y=1/2t^2
(d)-2 and 4 on x=1/2t^2, y=1/4t^2
Then use the formula y=1/2(p+q)x-apq to obtain the chords in parts (a)-(d)

PLEASE&THANKY0U VERY MUCH :)

  • 3unit maths - ,

    (d) is not a parabola since both x and y are proportional to the parameter t^2. Did you copy the problem correctly?

    These are four separate problems that can be all done the same way. Consider (a):

    t = x/2, so y = (1/4) x^2 is the equation of the parabola.
    When t = 1, x = 2 and y = 1
    When t = -3, x = -6 and y = 9
    The chord that they want connects these two points.
    The slope is 8/(-8) = -1
    y = -x + b
    1 = -2 + b
    b = 3
    y = -x + 3 is the chord equation, with
    -6 < x < 2

    You need to define a, p and q in the equation
    y=(1/2)(p+q)x-apq
    That is not the equation of a parabola.

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