Posted by TRACY-888 on Monday, April 6, 2009 at 5:23am.
(d) is not a parabola since both x and y are proportional to the parameter t^2. Did you copy the problem correctly?
These are four separate problems that can be all done the same way. Consider (a):
t = x/2, so y = (1/4) x^2 is the equation of the parabola.
When t = 1, x = 2 and y = 1
When t = -3, x = -6 and y = 9
The chord that they want connects these two points.
The slope is 8/(-8) = -1
y = -x + b
1 = -2 + b
b = 3
y = -x + 3 is the chord equation, with
-6 < x < 2
You need to define a, p and q in the equation
y=(1/2)(p+q)x-apq
That is not the equation of a parabola.
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