Posted by Phan on Sunday, April 5, 2009 at 5:00pm.
You want 0.700 M MnSO4 so you want 0.700 moles MnSO4 in 1 L of soln. For 100 mL, you will want 0.1 of that. You want to know grams and moles = grams/molar mass. You know moles and you know molar mass; calculate grams.
Then on the dilution, the easy way is to do it this way.
0.7 M x 1.00/20.00 = ?? but sometimes the easiest to understand is to change 0.7 M x 0.001 L (that's 1 mL) to moles, then put that number of moles in 20 mL, divide moles/L to convert to M. You should get the same answer.
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