Posted by **Shirley** on Friday, April 3, 2009 at 7:33pm.

How do you find the distance from the point to the line given the equation and the coordinates?

4x-2y-6=0 (1,1)

- Pre-Cal -
**bobpursley**, Friday, April 3, 2009 at 9:39pm
put the line in slope intercept form

y=mx+b

then,you know the slope of the perpendicular line is the negative reciprocal of m (new slope of perpendicular line=-1/m

So for the perpendicular line...

y=-1/m x + b

put in the point 1,1

1=-/m + b you know m, solve for b.

- Pre-Cal -
**Reiny**, Friday, April 3, 2009 at 11:37pm
there is a little formula for this question:

for Ax + By + C = 0

the distance from a point (p,q) to that line is

│Ap + Bq + C│/√(a^2+b^2)

so distance = │4-2-6│/√(16+4)

= 4/√20

= 4√20 /20

= 4√5/5

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