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September 30, 2014

September 30, 2014

Posted by **jaz** on Thursday, April 2, 2009 at 11:09am.

sin

cos

tan

csc

sec

cot

- pre calc -
**Reiny**, Thursday, April 2, 2009 at 11:19amdid you make a diagram?

you would have a right-angled triangle in the second quadrant with x=-2 and r=5

so

x^2 + y^2 = r^2

4 + y^2 = 25

y = ± √21

but we are in quadrant II, so y = +√21

now, knowing the trig rations in terms of x,y, and r, your question is easy

e.g. tan(angle) = y/x = - √21/2

sec(angle) = r/x = - 5/2

you do the rest.

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