ok i have to divide complex numbers:

question is: 1-2i+i^3/1+i

this is what i did:

1-2i+i(-i)/1+i
1-2i-i^2/1+i
1-2i-i(-1)/1+i
1-2i+i/1+i
1-3i/1+i*1-i/1-i
1-i-3i+3i^2/1-i+i-i^2
1-i-3i+3(-1)/1-i^2
1-i-3i-3/1-(-1)
1-4i-3/2
-2-4i/2
my answer is -2i-1

is that right?

ok i have to divide complex numbers:

question is: 1-2i+i^3/1+i

this is what i did:

1-2i+i(-i)/1+i
1-2i-i^2/1+i
1-2i-i(-1)/1+i
1-2i+i/1+i
1-3i/1+i*1-i/1-i
1-i-3i+3i^2/1-i+i-i^2
1-i-3i+3(-1)/1-i^2
1-i-3i-3/1-(-1)
1-4i-3/2
-2-4i/2
my answer is -2i-1

is that right?

To divide complex numbers, you can follow these steps:

1. Write the complex numbers in the form a + bi, where a and b are real numbers.
2. Simplify any expressions involving the imaginary unit i.

Now let's solve the expression you provided step by step:

1-2i+i^3/1+i

First, simplify the expression involving i:
i^3 is equal to -i because i^2 is -1, and multiplying by i again gives -i.

So now we have:
1 - 2i + (-i) / (1 + i)

To simplify further, we can multiply the numerator and denominator by the conjugate of the denominator (1 - i).

[(1 - 2i + (-i)) * (1 - i)] / [(1 + i) * (1 - i)]

Multiplying the numerator:
= (1 - 2i - i - 2i^2) * (1 - i)
= (1 - 2i - i + 2) * (1 - i)
= (3 - 3i) * (1 - i)
= 3 - 3i - 3i + 3i^2
= 3 - 6i - 3
= -6 - 6i

Multiplying the denominator:
= (1 + i) * (1 - i)
= 1 - i + i - i^2
= 1 - i + i + 1
= 2

Now we can divide the numerator by the denominator:
(-6 - 6i) / 2

Dividing both parts of the complex number by 2:
= -3 - 3i

So the simplified form of (1 - 2i + i^3) / (1 + i) is -3 - 3i.

Therefore, the answer is -3 - 3i, not -2i - 1.