The length of a rectangle is 5 cm more than twice the width. The perimeter of the rectangle is 34 cm. Find the dimensions of the rectangle.

if you let the width be w cm

isn't the length 2w + 5 ?

now form the equation for
perimeter = 34

let me know what you get.

aren't you supposed to form it for the width?

but forming one for the perimeter would be 2L+2w=34.

<< but forming one for the perimeter would be 2L+2w=34 >>

precisely!

but didn't it say " The length of a rectangle is 5 cm more than twice the width"
or
l = 5 + 2w , as I stated in my first reply.

so 2l + 2w = 34
2(5+2w) + 2w = 34
10 + 4w + 2w = 34
6w = 24
w = 4
then
l = 5 + 2w
= 5 + 8 = 13

check: is 13 five more than twice 4??
is 2(4) + 2(13) = 34 ?

mmmh?

thank you, i get it now

To find the dimensions of the rectangle, let's assign variables to the width and length of the rectangle. Let's call the width "W" and the length "L".

According to the information given, the length L is 5 cm more than twice the width W. We can write this as:

L = 2W + 5

The perimeter of a rectangle is given by the formula:

Perimeter = 2 * (Length + Width)

In this case, the perimeter is given as 34 cm. So we have:

34 = 2 * (L + W)

Now we can substitute the value of L from the first equation into the second equation:

34 = 2 * ((2W + 5) + W)

Simplifying this equation, we get:

34 = 2 * (3W + 5)

Now we distribute the 2 on the right side of the equation:

34 = 6W + 10

Subtracting 10 from both sides:

24 = 6W

Now, divide both sides by 6 to solve for W:

W = 4

Now that we know the width, we can substitute the value of W back into the first equation to find the length:

L = 2W + 5
L = 2(4) + 5
L = 8 + 5
L = 13

So the dimensions of the rectangle are width = 4 cm and length = 13 cm.