Posted by **Angie** on Wednesday, April 1, 2009 at 8:19pm.

The length of a rectangle is 5 cm more than twice the width. The perimeter of the rectangle is 34 cm. Find the dimensions of the rectangle.

- math -
**Reiny**, Wednesday, April 1, 2009 at 8:29pm
if you let the width be w cm

isn't the length 2w + 5 ?

now form the equation for

perimeter = 34

let me know what you get.

- math -
**Angie**, Wednesday, April 1, 2009 at 8:34pm
aren't you supposed to form it for the width?

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**Angie**, Wednesday, April 1, 2009 at 8:41pm
but forming one for the perimeter would be 2L+2w=34.

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**Reiny**, Wednesday, April 1, 2009 at 8:56pm
<< but forming one for the perimeter would be 2L+2w=34 >>

precisely!

but didn't it say " The length of a rectangle is 5 cm more than twice the width"

or

l = 5 + 2w , as I stated in my first reply.

so 2l + 2w = 34

2(5+2w) + 2w = 34

10 + 4w + 2w = 34

6w = 24

w = 4

then

l = 5 + 2w

= 5 + 8 = 13

check: is 13 five more than twice 4??

is 2(4) + 2(13) = 34 ?

mmmh?

- math -
**Angie**, Wednesday, April 1, 2009 at 9:03pm
thank you, i get it now

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