Monday

July 28, 2014

July 28, 2014

Posted by **jake** on Wednesday, April 1, 2009 at 10:38am.

- college algebra -
**Reiny**, Wednesday, April 1, 2009 at 11:51amfor the x-intercept let y = 0

x^3 + 7x^2 + 10x = 0

x(x^2 + 7x + 10) = 0

x(x+2)(x+5) = 0

so x = 0, -2, -5

(your x-intercepts)

for the y-intercept, let x = 0

then of course y=0

so 3 x-intercepts, one y-intercept

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