when benzoic acid and quinine is dissolved to dichlromethane and 2M NaOh, what is the organic layer being formed?
(i have sodium benzoate as aqueous layer of the product. is this right?)
Quinine would be the Organic Layer.
And, Sodium Benzoate would be in the Aqueous Layer.
To determine the organic layer formed when benzoic acid and quinine are dissolved in dichloromethane (CH2Cl2) and 2M NaOH, we need to understand the solubility properties of these compounds.
When benzoic acid (C6H5COOH) reacts with sodium hydroxide (NaOH), it undergoes an acid-base neutralization reaction. The acidic proton (H+) from benzoic acid is replaced by the sodium ion (Na+), resulting in the formation of sodium benzoate (C6H5COONa).
C6H5COOH + NaOH → C6H5COONa + H2O
Sodium benzoate, being a salt, generally exists in an ionic form and is highly soluble in water (aqueous solution). So yes, sodium benzoate is likely to form the aqueous layer in the mixture.
On the other hand, quinine is an organic compound and is more likely to be soluble in the organic solvent dichloromethane (CH2Cl2) rather than in water.
So, when benzoic acid and quinine are dissolved in dichloromethane (CH2Cl2) and 2M NaOH, you would expect to have two layers formed:
1. The top layer would be the organic layer, consisting mainly of CH2Cl2 and any dissolved quinine.
2. The bottom layer (aqueous layer) would contain the sodium benzoate and residual NaOH.
Remember to properly separate the two layers using a separatory funnel or similar technique to collect the organic layer.