Math Algebra
posted by Edward on .
I’m working on factoring trinomials of the form ax2 + bx + c & perfect square trinomials. This chapter explains that a further method will be needed to conduct a trial and check process, in which the middle term is the sum of the products.
Here’s the problem as follows:
4y2  20y + 25 = (2y5) ( )

You need another 2y to get 4y
4y2  20y + 25 = (2y5) (2y )
now that5*2y = 10y
so the product of 5 and the last term must be 25 so 5
so
(2y5)(2y5)