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March 1, 2015

March 1, 2015

Posted by **stephanie** on Tuesday, March 31, 2009 at 9:36pm.

I got... The least upper bound of the zeros of f(x) is -0.7549

- pre. cal. -
**Reiny**, Tuesday, March 31, 2009 at 10:08pmas you found out, there are no integral zeros of the function.

There is only one real intercept and you found that correctly. (how did you find that anyway ?)

My guess would be that they want the next lowest integer value to that zero, perhaps -1 ??? or is it 0 ??

not sure about the wording though.

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