MATH:Solving with 3 variables
posted by Brad on .
03p0.25r03q=0
0.8p0.6r0.05q=0
0.9p0.15r0.65q=0
I don't know if this help but i think p+q=1.

should there be decimal places in the first and third terms of
03p0.25r03q=0 ?
anyway, since all 3 constants are equal to zero, the solution would be (0,0,0)