Posted by **CC** on Tuesday, March 31, 2009 at 5:07pm.

The co-efficient for static friction for a 5 kg box on a floor is .72. How much force if required to start the box sliding?

I worked it as follows:

Force of friction=Force normal * co-effic. of friction which is .72*5*9.8=35.28 but answer in back of my book says this is wrong. Where did I err?

- Physics -
**Carissine**, Tuesday, March 31, 2009 at 5:38pm
Force of Friction= Force of the normal*co-effic...

Coefficient= .72

Normal Force= mass*g

9.81*5

49.05

Solve: 49.05*0.72

35.316 or 35.32

Is that what you got? If it is, you're right. If not, recheck the book, it may be that you are looking at the wrong answer.

- Physics -
**CC**, Tuesday, March 31, 2009 at 5:51pm
Yes, that's my answer too. Incorrect answers at the back of the book drive me crazy! thanks for confirming!

## Answer This Question

## Related Questions

- physics - box full of books rests on a wooden floor. The normal force the floor...
- Physics - an 88kg cardboard box is being pulled along a level floor. the ...
- 11 grade physics - A force of 23.0 N is required to start a 3.0 kg box moving ...
- Physics - a force of 48.0N is required to start a 5.Okg box moving across a ...
- Physics - A force of 40 N is required to start a 5 kg box moving across a ...
- Physics - A force of 23.0 N is required to start a 3.1 kg box moving across a ...
- physics - 1. A student is dragging a 5 kg box along the floor. He pulls on the ...
- Physics - 4. A force of 48 N is required to start a 7.8 kg box moving across a ...
- Physics - A box with a mass of 7.00 kg is at rest on a ramp that is at an angle ...
- Physics 204 - I have a few questions. 1.The coefficient of sliding friction ...

More Related Questions