Post a New Question


posted by on .

The co-efficient for static friction for a 5 kg box on a floor is .72. How much force if required to start the box sliding?
I worked it as follows:
Force of friction=Force normal * co-effic. of friction which is .72*5*9.8=35.28 but answer in back of my book says this is wrong. Where did I err?

  • Physics - ,

    Force of Friction= Force of the normal*co-effic...

    Coefficient= .72
    Normal Force= mass*g
    Solve: 49.05*0.72
    35.316 or 35.32

    Is that what you got? If it is, you're right. If not, recheck the book, it may be that you are looking at the wrong answer.

  • Physics - ,

    Yes, that's my answer too. Incorrect answers at the back of the book drive me crazy! thanks for confirming!

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question