Posted by CC on Tuesday, March 31, 2009 at 5:07pm.
The coefficient for static friction for a 5 kg box on a floor is .72. How much force if required to start the box sliding?
I worked it as follows:
Force of friction=Force normal * coeffic. of friction which is .72*5*9.8=35.28 but answer in back of my book says this is wrong. Where did I err?

Physics  Carissine, Tuesday, March 31, 2009 at 5:38pm
Force of Friction= Force of the normal*coeffic...
Coefficient= .72
Normal Force= mass*g
9.81*5
49.05
Solve: 49.05*0.72
35.316 or 35.32
Is that what you got? If it is, you're right. If not, recheck the book, it may be that you are looking at the wrong answer.

Physics  CC, Tuesday, March 31, 2009 at 5:51pm
Yes, that's my answer too. Incorrect answers at the back of the book drive me crazy! thanks for confirming!
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