Posted by Jennifer on .
Solve 3y^2 + 4y  2 greater than/equal to 0
3y^2 + 4y  2 ≥ 0
3y^2 + 4y  2 = 0
y = [4 ± sqrt (4^2  4(3)(2)]/(2 • 3) = (4 ± sqrt 40)/6 = (4 ± 2 rad 10)/6 = (2 ± rad 10)/3
Is this right?

Pre Cal. 
Reiny,
you have solved the "equation" but you were dealing with an inequation.
the values of (2 ± √10)/3 are the intercepts on a ynumber line.
so the solution would be
y ≤ (2  √10)/3 OR y ≥ (2 + √10)/3
too bad it did not factor, it would have been easier to see.