Monday
March 30, 2015

Homework Help: Pre Cal.

Posted by Jennifer on Tuesday, March 31, 2009 at 1:20pm.

Solve 3y^2 + 4y - 2 greater than/equal to 0

3y^2 + 4y - 2 ≥ 0
3y^2 + 4y - 2 = 0
y = [-4 ± sqrt (4^2 - 4(3)(-2)]/(2 • 3) = (-4 ± sqrt 40)/6 = (-4 ± 2 rad 10)/6 = (-2 ± rad 10)/3

Is this right?

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

ALGEBRA - 2nd posting - my mistake When will the dependent variable in the ...
ALGEBRA - When will the dependent variable in the equation Y=[(sqrt)(x+4-3)] ...
Algebra - When will the dependent variable in the equation Y=[(sqrt)(x+4-3)] ...
PRE-ALGEBRA MRS.SUE PLEASE!!!!!!!!! - 1. 5h – 9 = –16 + 6h (1 point) 4 –7 7 10 2...
PRE-ALGEBRA - 1. 5h – 9 = –16 + 6h (1 point) 4 –7 7 10 2. 4x + 4 = 9x – 36 (1 ...
Mathforme - 5. 4x + 2 = x + 8. (1 point) x = 4 x = 3 x = 2 x = 1 Solve the ...
kbMath - 5.   4x + 2 = x + 8.  (1 point) x = 4 x = 3 x = 2 x = 1 Solve the ...
Pre Cal. - 1. Use half-angle identity to find the exact value of cos165. MY ...
pre-cal - Find the roots of the function f(x)= x^2+2x+2 Determine f(x) a) (x+1-i...
Pre-Cal(Please check) - 1)f(x) = -x + sqrt 4 - x^2 Find f(-2) -(-2) + sqrt 4...

Members