Friday

April 18, 2014

April 18, 2014

Posted by **Andrew** on Monday, March 30, 2009 at 10:26pm.

CdS + 2e- --> Cd + S-2 E° = -1.21V

Cd+2 + 2e- --> Cd E° = -0.402V

---------------------------------------

CdS + Cd --> Cd + Cd+2 + S-2 E° = -0.808

===================================

What I tried was:

E = E° - (0.0591/n)log(K)

where E is zero since it is in equilibrium, and n is 2 because there are 2moles of electrons per mole of Cd.

I reversed the net equation because I was looking for the Ksp of CdS.

When I did this, I got 4.53*10^28, but the actual answer was 3.9*10^28.

Please help!

Thanks a lot.

I hope the error was from rounding up. :)

**Related Questions**

college chemistry - Cadmium sulfide (CdS) is used in some semiconductor ...

Inorganic chemistry - Given the following two half-reactions, determine which ...

chemistry... HELP - Equilibrium constant question!!!? Standard reduction ...

Inorganic chemistry - Calculate E naught cell for the reaction b 5Cd(s) + 2MnO4...

Inorganic chemistry - Given the following standard reduction potentials, Fe^2+(...

Inorganic chemistry - Given the following standard reduction potentials, Fe^2+(...

Math - Tell whose CD collection has the greater ratio of rock CDs to total CDs. ...

Chemistry - Yellow CdS pigment is prepared by reacting ammonium sulfide with ...

Chemistry - Calculate the cell potential for the following reaction as written ...

finite MAth - dent who wants to buy 3 CDs, but assume that there are 4 CDs ...