Homework Help: Algebra

Posted by Alicia on Monday, March 30, 2009 at 7:45pm.

I need to simplify this.

(2^-1 . 7^-4)^-2

I thought that 2 was suppose to be multiplied with the -1, but that doesn't seem to make sense so I am confused. I know that PEDMAS needs to be used, just don't know how to apply it. Any help is appreciated!

Algebra - Reiny, Monday, March 30, 2009 at 8:12pm
(2^-1 . 7^-4)^-2
= (2^2)(7^8)
= 23059204
Algebra - Laurie, Monday, March 30, 2009 at 8:16pm
Those aren't any of my choices Here is what i got

2^2 . 7^8

2^5 . 7^5

1/2^5 . 7^5

1/2^2 . 7 ^8
Algebra - Reiny, Monday, March 30, 2009 at 8:27pm
sorry I went to the effort of calculating
2^2 . 7^8 for you.
Algebra - Laurie, Monday, March 30, 2009 at 8:37pm
Thanks! That is what I thought, but why is this the answer? How does the probelm work it self out to be like that?
Algebra - Anonymous, Tuesday, March 31, 2009 at 1:46pm
multiply each of the inside terms by the outside term.

2^-1*1^-2 = combine exponents = 2^2

7^-4*1^-2 = combine exponents = 7^8

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