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July 29, 2014

July 29, 2014

Posted by **sh** on Sunday, March 29, 2009 at 7:23pm.

1)(n-3)!

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n!

2) (n+4)!

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(n+2)!

- math -
**bobpursley**, Sunday, March 29, 2009 at 7:30pmI will do one. Take the greater number, and expand it. for instance, the first

(n-3)!/(n*(n-1)(n-2)(n-3)!)

the (n-3)! terms divide out..

1/(n)(n-1)(n-2)

- math -
**sh**, Sunday, March 29, 2009 at 7:35pmthen the second one would be

(n+4)!/((n+1)(n+2)(n+3)(n+4)(n+2)!)

=

1/(n+1)(n+2)^2 (n+3) ?

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