posted by purpletree on .
Find two consecutive integers, the sum of whose squares is 1 more than twelve times the larger.
(Please provide the steps/explanation for solving this problem)
two consecutive integers: x and x+1
<the sum of whose squares is 1 more than twelve times the larger..>
x^2 + (x+1)^2 = 12(x+1) + 1
expand and solve as a quadratic equation.
(see if you can come up with 6,7 or -1,0 )
Thanks for the help. :)