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March 26, 2017

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Find two consecutive integers, the sum of whose squares is 1 more than twelve times the larger.
(Please provide the steps/explanation for solving this problem)

  • Quadratic Equations - ,

    two consecutive integers: x and x+1

    <the sum of whose squares is 1 more than twelve times the larger..>
    x^2 + (x+1)^2 = 12(x+1) + 1

    expand and solve as a quadratic equation.
    (see if you can come up with 6,7 or -1,0 )

  • Quadratic Equations - ,

    Thanks for the help. :)

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