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Chemistry

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Calculate [Fe^2]+ when the cell reaction reaches equilibrium?

A voltaic cell is constructed based on the following reaction and initial concentrations:
Fe^2+,( 0.0055 M ) + Ag+,( 2.5 M ) ----> Fe^3+,( 0.0055 M ) + Ag(s)


Calculate [Fe^2]+ when the cell reaction reaches equilibrium

can someone please explain how to do this?

  • Chemistry -

    I forgot to mention that forward arrow is suppose to be an equilibrium arrow forward/reverse

  • Chemistry -

    First solve K or Q using the Nestern (I think that is how you spell it, if not shh)

    then find the change in equilibrium

    next use the quadratic equation to solve X and subtract with the concentration you are trying to find [Fe2+]

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