posted by Sandra on .
Calculate [Fe^2]+ when the cell reaction reaches equilibrium?
A voltaic cell is constructed based on the following reaction and initial concentrations:
Fe^2+,( 0.0055 M ) + Ag+,( 2.5 M ) ----> Fe^3+,( 0.0055 M ) + Ag(s)
Calculate [Fe^2]+ when the cell reaction reaches equilibrium
can someone please explain how to do this?
I forgot to mention that forward arrow is suppose to be an equilibrium arrow forward/reverse
First solve K or Q using the Nestern (I think that is how you spell it, if not shh)
then find the change in equilibrium
next use the quadratic equation to solve X and subtract with the concentration you are trying to find [Fe2+]